College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 279: 121

Answer

$(f-g)(3)=0$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find the value of the given expression, $ (f-g)(3) ,$ use the definition of the appropriate function operation. Then substitute the values in the given table. $\bf{\text{Solution Details:}}$ Using $(f-g)(x)=f(x)-g(x),$ then \begin{array}{l}\require{cancel} (f-g)(3)=f(3)-g(3) \text{ (Equation *)} .\end{array} Based on the given table, when $x= 3 ,$ the value of $f(x)$ is $ 9 .$ Hence, $ f(3)=9 .$ Based on the given table, when $x= 3 ,$ the value of $g(x)$ is $ 9 .$ Hence, $ g(3)=9 .$ By substitution, Equation * becomes \begin{array}{l}\require{cancel} (f-g)(3)=f(3)-g(3) \\\\ (f-g)(3)=9-9 \\\\ (f-g)(3)=0 .\end{array}
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