College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 279: 123

Answer

$\left( \dfrac{f}{g} \right)(0)\text{ is undefined}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find the value of the given expression, $ \left( \dfrac{f}{g} \right)(0) ,$ use the definition of the appropriate function operation. Then substitute the values in the given table. $\bf{\text{Solution Details:}}$ Using $\left( \dfrac{f}{g} \right)(x)=\dfrac{f(x)}{g(x)},$ then \begin{array}{l}\require{cancel} \left( \dfrac{f}{g} \right)(0)=\dfrac{f(0)}{g(0)} \text{ (Equation *)} .\end{array} Based on the given table, when $x= 0 ,$ the value of $f(x)$ is $ 5 .$ Hence, $ f(0)=5 .$ Based on the given table, when $x= 0 ,$ the value of $g(x)$ is $ 0 .$ Hence, $ g(0)=0 .$ By substitution, Equation * becomes \begin{array}{l}\require{cancel} \left( \dfrac{f}{g} \right)(0)=\dfrac{f(0)}{g(0)} \\\\ \left( \dfrac{f}{g} \right)(0)=\dfrac{5}{0} \\\\ \left( \dfrac{f}{g} \right)(0) \text{ is undefined} .\end{array}
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