Answer
$(f\circ g)(2)=1$
Work Step by Step
$$(f\circ g)(2)=f(g(2))$$
Note from the graph of $g$, the value of $g(2)$ is $2$. So, equations becomes:
$$(f\circ g)(2)=f(g(2))=f(2)$$
Note from the graph of $f$, the value of $f(2)$ is $1$. So, equations becomes:
$$(f\circ g)(2)=f(g(2))=f(2)=1$$
