## College Algebra (11th Edition)

Published by Pearson

# Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises - Page 85: 31

#### Answer

Conditional Equation; Solution: 0.

#### Work Step by Step

$2(x-8)=3x+16$ Distribute all appropriate terms. $2x-16=3x-16$ Subtract 3x and add 16. $-x=0$ You're left with only one solution, and so the equation is a conditional equation. $x=0$

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