College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises: 38

Answer

A contradiction.

Work Step by Step

$x+k=x,k\ne0$ We can check the possibilities of this condition by setting x equal to 0 and setting k equal to 1. $(0)=(1)=1$ The final equation yields a problem. By setting k to any number except 0 and with x held constant, x can never equal its original value before the value of k was added. Therefore, the equation is a contradiction. $0\ne1$
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