College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises - Page 85: 36


The equation is a contradiction.

Work Step by Step

Distribute through the parenthesis. $-12x-6-3x+12=-15x+1$ Add/Subtract like terms. $-15x+6=-15x+1$ Add $15x$ to each side. Because you are left with 2 unequal constants, no value of $x$ will satisfy the given conditions. $6=1$
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