College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises: 59

Answer

Part A: $I=63$ Part B: $\$3213$

Work Step by Step

Part A: $I=PRT$ (Interest Formula) P(price)=3150, R(interest rate)=.04, T(time)=6/12 $I=3150(.04)(6/12)$ Solution. Interest is $\$63$ $I=63$ Part B: Interest is 63. Price is 3150. $63+3150=3213$ The 63 is the interest you got in 59a and you add that to the original price in 59a which 3150. $\$3213$
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