# Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises - Page 84: 30

Identity; Solution: All Real Numbers.

#### Work Step by Step

$\frac{1}{2}(6x+20)=x+4+2(x+3)$ Distribute and add appropriate terms. $3x+10=3x+10$ All terms cancel out leaving you with a true statement (0=0), and the equation is therefore an identity. $0=0$ Identity; Solution: All Real Numbers.

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