College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 43



Work Step by Step

We simplify: $\displaystyle \sqrt[3]{16x^4}-\sqrt[3]{2x}=\sqrt[3]{8*2x^3x}-\sqrt[3]{2x}=2x\sqrt[3]{2x}-1\sqrt[3]{2x}=(2x-1)\sqrt[3]{2x}$
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