College Algebra (10th Edition)

$x^2y$
We use the rules of exponents and radicals to obtain: $\displaystyle \sqrt[5]{x^{10}y^5}=(x^{10}y^{5})^{1/5}=(x^{10})^{1/5}(y^{5})^{1/5}=x^2y^1=x^2y$