College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 23

Answer

$6\sqrt{x}$

Work Step by Step

We use the rules of exponents and radicals to obtain: $\displaystyle \sqrt[2]{36x}=\sqrt[2]{6^2x}=6\sqrt{x}$
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