College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 26



Work Step by Step

We use the rules of exponents and radicals to obtain: $\displaystyle \sqrt[3]{-40x^{14}y^{10}}=\sqrt[3]{-8*5*x^{14}y^{10}}=\sqrt[3]{(-2)^{3}5x^{12}x^2y^{9}y}=-2x^4y^3\sqrt[3]{5x^2y}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.