Answer
$x^3y^2$
Work Step by Step
We use the rules of exponents and radicals to obtain:
$\displaystyle \sqrt[4]{x^{12}y^8}=(x^{12}y^{8})^{1/4}=(x^{12})^{1/4}(y^{8})^{1/4}=x^3y^2$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 19
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