Answer
$-3013$
Work Step by Step
The sequence is arithmetic with common difference d=$-3$,
$a_{1}=2.$
The sum $S_{n}$ of the first $n$ terms of $\left\{a_{n}\right\}$:
$S_{n}=\displaystyle \frac{n}{2}\left[2a_{1}+(n-1)d\right]$
$S_{46}=\displaystyle \frac{46}{2}\left[2(2)-3(46-1)\right]$
$=23(4-135)$
$=-3013$
