## College Algebra (10th Edition)

$17$
In an arithmetic sequence, the nth term is $a_{n}=a_{1}+(n-1)d$ Given the 5th term, $12=a_{1}+(5-1)5$ ... solve for $a_{1}$ $12-20=a_{1}$ $a_{1}=-8$ So $a_{6}=-8+(6-1)5=17$