Answer
$17$
Work Step by Step
In an arithmetic sequence, the nth term is
$a_{n}=a_{1}+(n-1)d$
Given the 5th term,
$12=a_{1}+(5-1)5$ ... solve for $a_{1}$
$12-20=a_{1}$
$a_{1}=-8$
So
$a_{6}=-8+(6-1)5=17$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Section 9.2 - Arithmetic Sequences - 9.2 Assess Your Understanding - Page 654: 3
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