Answer
common difference = $3$
The first four terms are: $4, 7, 10, 13$
Work Step by Step
To find the first four terms, substitute $1, 2, 3, 4$ for $n$ in the given formula.
$b_1 = 3(1)+1 = 3+1= 4$
$b_2= 3(2)+1 =6+1=7$
$b_3 = 3(3)+1=9+1=10$
$b_4 = 3(4)+1 = 12+1 = 13$
The terms increase by $3$ units, so the sequence is arithmetic with a common difference of $3$.