College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.2 - Arithmetic Sequences - 9.2 Assess Your Understanding - Page 654: 10

Answer

common difference = $3$ The first four terms are: $4, 7, 10, 13$

Work Step by Step

To find the first four terms, substitute $1, 2, 3, 4$ for $n$ in the given formula. $b_1 = 3(1)+1 = 3+1= 4$ $b_2= 3(2)+1 =6+1=7$ $b_3 = 3(3)+1=9+1=10$ $b_4 = 3(4)+1 = 12+1 = 13$ The terms increase by $3$ units, so the sequence is arithmetic with a common difference of $3$.
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