Answer
$301$
Work Step by Step
There is a constant difference, $3$, between terms.
The terms are part of an arithmetic sequence.
nth Term of an Arithmetic Sequence:
$a_{n}=a_{1}+(n-1)d$
$ 41=2+3(n-1)\qquad$... solve for n
$39=3(n-1)$
$13=(n-1)$
$n=14$
There are $14$ terms in the sum.
The terms of the sum
are the first $14$ terms of an arithmetic sequence, $a_{1}=2, d=3.$
Sum of the First $n$ Terms of an arithmetic sequence:
$S_{n}=\displaystyle \frac{n}{2}\left(a_{1}+a_{n}\right)$
$S_{14}=\displaystyle \frac{14}{2}\left(2+41\right)=7\cdot 43=301$
