College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 678: 6

Answer

See below.

Work Step by Step

As we can see the numerators are always $1$, the denominators start at $1$ and increase by $1$ at each term until they reach $13$. Also the signs are alternating, thus the formula is: $\sum_{i=1}^{13} (-1)^{i+1}\frac{1}{i}$
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