College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 678: 10

Answer

See below.

Work Step by Step

In order for a sequence to be arithmetic, the difference of all consecutive terms must be constant. Hence here: $4-0=4=8-4=d$, which is constant thus it is an arithmetic sequence. The sum of the first $n$ terms of an arithmetic sequence can be obtained by the following formula: $\frac{n(a_1+a_n)}{2},$ where $a_1$ is the first term, $a_n$ is the nth term and $n$ is the number of terms. The nth term of an arithmetic sequence can be obtained by the following formula: $a_n=a_1+(n-1)d$, where $a_1$ is the first term and $d$ is the common difference. Hence here: $a_{n}=0+(n-1)4=4n-4$ Thus the sum:$\frac{n(0+4n-4)}{2}=n(2n-2)$
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