Answer
See below.
Work Step by Step
$a_1=(-1)^1\frac{1+3}{1+2}=-\frac{4}{3}$.
$a_2=(-1)^2\frac{2+3}{2+2}=\frac{5}{4}$.
$a_3=(-1)^3\frac{3+3}{3+2}=-\frac{6}{5}$.
$a_4=(-1)^4\frac{4+3}{4+2}=\frac{7}{6}$.
$a_5=(-1)^5\frac{5+3}{5+2}=-\frac{8}{7}$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Review Exercises - Page 678: 1
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