Answer
See below.
Work Step by Step
$\sum_{k=1}^{4} (4k+2)=(4(1)+2)+(4(2)+2)+(4(3)+2)+(4(4)+2)=6+10+14+18=48$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Review Exercises - Page 678: 5
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