College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 678: 5


See below.

Work Step by Step

$\sum_{k=1}^{4} (4k+2)=(4(1)+2)+(4(2)+2)+(4(3)+2)+(4(4)+2)=6+10+14+18=48$
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