## College Algebra (10th Edition)

Published by Pearson

# Chapter 9 - Review Exercises - Page 678: 5

See below.

#### Work Step by Step

$\sum_{k=1}^{4} (4k+2)=(4(1)+2)+(4(2)+2)+(4(3)+2)+(4(4)+2)=6+10+14+18=48$

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