College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Review Exercises - Page 678: 2

Answer

See below.

Work Step by Step

$c_1=\frac{2^1}{1^2}=\frac{2}{1}=2$ $c_2=\frac{2^2}{2^2}=\frac{4}{4}=1$ $c_3=\frac{2^3}{3^2}=\frac{8}{9}$ $c_4=\frac{2^4}{4^2}=\frac{16}{16}=1$ $c_5=\frac{2^5}{5^2}=\frac{32}{25}$
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