College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 37

Answer

$x=4$ $y=3$ $(4,3)$

Work Step by Step

$\frac{1}{2}x+\frac{1}{3}y=3$ $(1)$ $\frac{1}{4}x-\frac{2}{3}y=-1$ $(2)$ Multiply Equation $(1)$ by 2 $x+\frac{2}{3}y=6$ $(1)$ $\frac{1}{4}x-\frac{2}{3}y=-1$ $(2)$ Add Equation $(1)$ from Equation $(2)$ $\frac{5}{4}x=5$ $x=4$ Substitute back to Equation $(2)$ $\frac{1}{4}(4)-\frac{2}{3}y=-1$ $1+1=\frac{2}{3}y$ $y=3$
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