College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 30

Answer

$x=1$ $y=-\frac{4}{3}$ $(1,-\frac{4}{3})$

Work Step by Step

$3x+3y = -1$ $(1)$ $4x+y=\frac{8}{3}$ $(2)$ Multiply Equation $(2)$ by 3 $3x + 3y = -1$ $(1)$ $12x + 3y = 8$ $(2)$ Subtract Equation $(1)$ from Equation $(2)$ $9x=9$ $x=1$ Substitute this to Equation $(2)$ $4(1) + y=\frac{8}{3}$ $4+y=\frac{8}{3}$ $y=\frac{8}{3}-4$ $y=-\frac{4}{3}$
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