## College Algebra (10th Edition)

In order to verify that the given point is a solution, we substitute the values of all 3 variables into both equations to ensure that they produce a true result: $$4(2)-1 =7 \\ 7=7$$ For equation two: $$8(2) + 5(-3)-1=0 \\0=0$$ For equation three: $$-2-(-3)+5(1)=6 \\6=6$$ All equations are true, so the solution is correct.