Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 26

$x=-\frac{5}{3}$ $y=1$ $(-\frac{5}{3},1)$

$2x + 4y = \frac{2}{3}$ $(1)$ $3x-5y=-10$ $(2)$ Multiply Equation $(1)$ by 3 and Equation $(2)$ by 2 $6x+12y=2$ $(1)$ $6x-10y=-20$ $(2)$ Subtract Equation $(1)$ and Equation $(2)$ $22y = 22$ $y=1$ Substitute into Equation $(2)$ $3x-5(1)=-10$ $3x-5=-10$ $3x=-5$ $x=-\frac{5}{3}$