College Algebra (10th Edition)

{$-12$}
$\frac{-4}{x+4}=\frac{-3}{x+6}$ Where $x\ne-4, x\ne-6$ $-4(x+6)=-3(x+4)$ Use cross multiplication. $-4x-24=-3x-12$ Distribute. $-4x-24+24=-3x-12+24$ Add 24 to both sides. $-4x=-3x+12$ $-4x+3x=-3x+3x+12$ Add 3x to both sides. $-x=12$ $\frac{-x}{-1}=\frac{12}{-1}$ $x=-12$ The solution is {-12}