## College Algebra (10th Edition)

The solution is {$34$}.
$\frac{5}{2x-3}=\frac{3}{x+5}$ Where $x\ne\frac{3}{2}, x\ne-5$ $5(x+5)=3(2x-3)$ Use cross multiplication. $5x+25=6x-9$ Distribute. $5x-6x+25=6x-6x-9$ Subtract 6x from both sides. $-x+25=-9$ $-x+25-25=-9-25$ Add -25 to both sides. $-x=-34$ $\frac{-x}{-1}=\frac{-34}{-1}$ $x=34$ The solution is {$34$}.