## College Algebra (10th Edition)

{$-1$}
$x(2x-3)=(2x+1)(x-4)$ Distribute, multiply and combine like terms. $2x^2-3x=2x^2-8x+x-4$ $2x^2-2x^2-3x=2x^2-2x^2-7x-4$ Subtract $2x^2$ from both sides. $-3x+7x=-7x+7x-4$ Add $7x$ to both sides. $4x=-4$ $\frac{4}{4}x=\frac{-4}{4}$ Divide both sides by 4. $x=-1$ The solution is {$-1$}