College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding: 35

Answer

$p=2$

Work Step by Step

$\frac{2}{3}p=\frac{1}{2}p+\frac{1}{3}$ $\longrightarrow$ addition property of equality $\frac{2}{3}p-\frac{1}{2}p=\frac{1}{2}p+\frac{1}{3}-\frac{1}{2}p$ $\longrightarrow$ combine like terms $\frac{1}{6}p=\frac{1}{3}$ $\longrightarrow$ multiplication property of equality $\frac{1}{6}p\times6=\frac{1}{3}\times6$ $\longrightarrow$ simplify $p=2$
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