College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 90: 50



Work Step by Step

$w(4-w^2)=8-w^2$ $4w-w^3=8-w^3$ Distribute. $4w-w^3+w^3=8-w^3+w^3$ Add $w^3$ to both sides. $4w=8$ $\frac{4}{4}w=\frac{8}{4}$ Divide both sides by 4. $w=2$ The solution is {$2$}.
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