## College Algebra (10th Edition)

{$2$}
$w(4-w^2)=8-w^2$ $4w-w^3=8-w^3$ Distribute. $4w-w^3+w^3=8-w^3+w^3$ Add $w^3$ to both sides. $4w=8$ $\frac{4}{4}w=\frac{8}{4}$ Divide both sides by 4. $w=2$ The solution is {$2$}.