Answer
$(y+5)(y+8)$.
Work Step by Step
The given polynomial is
$=y^2+13y+40$
Standard form is $x^2+bx+c$.
We have $b=13$ and $c=40$.
$b$ and $c$ is positive.
Factor pair of $40$, whose sum is $13$:
$5,8$
The values of $p$ and $q$ are $5$ and $8$.
Hence, the factor of the polynomial is $(y+p)(y+q)=(y+5)(y+8)$.
Check:-
$=(y+5)(y+8)$
$=y^2+8y+5y+40$
$=y^2+13y+40$
True.
