Answer
$(y-10)(y+3)$.
Work Step by Step
The given polynomial is
$=-7y+y^2-30$
$=y^2-7y-30$
Standard form is $x^2+bx+c$.
We have $b=-30$ and $c=-7$.
$b$ and $c$ is negative.
Factor pair of $-30$, whose sum is $-7$:-
$-10,3$
The values of $p$ and $q$ are $-10$ and $3$.
Hence, the factor of the polynomial is $(y+p)(y+q)=(y-10)(y+3)$.
Check:-
$=(y-10)(y+3)$
$=y^2+3y-10y-30$
$=y^2-7y-30$
True.
