Answer
$(n-2)(n+6)$.
Work Step by Step
The given polynomial is
$=n^2+4n-12$
Standard form is $x^2+bx+c$.
We have $b=4$ and $c=-12$.
$b$ is positive and $c$ is negative.
Factor pair of $-12$, whose sum is $4$:-
$-2,6$
The values of $p$ and $q$ are $-2$ and $6$.
Hence, the factor of the polynomial is $(n+p)(n+q)=(n-2)(n+6)$.
Check:-
$=(n-2)(n+6)$
$=n^2+6n-2n-12$
$=n^2+4n-12$
True.
