Answer
$(x-1)(x+4)$.
Work Step by Step
The given polynomial is
$=x^2+3x-4$
Standard form is $x^2+bx+c$.
We have $b=3$ and $c=-4$.
$b$ is positive and $c$ is negative.
Factor pair of $-4$, whose sum is $3$:-
$-1,4$
The values of $p$ and $q$ are $-1$ and $4$.
Hence, the factor of the polynomial is $(x+p)(x+q)=(x-1)(x+4)$.
Check:-
$=(x-1)(x+4)$
$=x^2+4x-x-4$
$=x^2+3x-4$
True.
