Answer
$\sqrt[3] {\frac{27}{x^2}}$
Work Step by Step
$3x^{-\frac{2}{3}}=3^1(\frac{1}{x})^{\frac{2}{3}}=3^{\frac{3}{3}}\sqrt[3] {\frac{1^2}{x^2}}=\sqrt[3] {3^3}\sqrt[3] {\frac{1}{x^2}}=\sqrt[3] {27\frac{1}{x^2}}=\sqrt[3] {\frac{27}{x^2}}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 25: 59
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