Answer
(a) $6x\sqrt {2x}$
(b) $3y^2\sqrt {6x}$
Work Step by Step
(a) $\sqrt {72x^3}=\sqrt {36\times2x^2x}=\sqrt {6^2\times2x^2x}=6x\sqrt {2x}$
(b) $\sqrt {54xy^4}=\sqrt {9\times6x(y^2)^2}=\sqrt {3^2\times6x(y^2)^2}=3y^2\sqrt {6x}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 25: 45
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