Answer
$3\sqrt 6-3\sqrt 5=3(\sqrt 6-\sqrt 5)$
Work Step by Step
$\frac{3}{\sqrt 5+\sqrt 6}=\frac{3}{\sqrt 6+\sqrt 5}=\frac{3}{\sqrt 6+\sqrt 5}\frac{\sqrt 6-\sqrt 5}{\sqrt 6-\sqrt 5}=\frac{3\sqrt 6-3\sqrt 5}{\sqrt 6\sqrt 6-\sqrt 6\sqrt 5+\sqrt 5\sqrt 6-\sqrt 5\sqrt 5}=\frac{3\sqrt 6-3\sqrt 5}{(\sqrt 6)^2-(\sqrt 5)}=\frac{3\sqrt 6-3\sqrt 5}{6-5}=\frac{3\sqrt 6-3\sqrt 5}{1}=3\sqrt 6-3\sqrt 5$
