Answer
(a) $2x\sqrt[3] {2x^2}$
(b) $\frac{5x}{y^2}\sqrt 3$
Work Step by Step
(a) $\sqrt[3] {16x^5}=\sqrt[3] {2^3(2)x^3x^2}=2x\sqrt[3] {2x^2}$
(b) $\sqrt {75x^2y^{-4}}=\sqrt {5^2(3)x^2(y^{-2})^2}=5xy^{-2}\sqrt 3=\frac{5x}{y^2}\sqrt 3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 25: 47
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
