## Algebra and Trigonometry 10th Edition

For this problem, Equation 1: x - y = -4 Equation 2: $x^{2}$ - y = -2 For substitution we need to solve for a variable. In this problem, we will solve for y in Equation 1 to get Equation 3: y = x + 4 (Equation 3) We then substitute that into Equation 2 and solve for x: $x^{2}$ - (x + 4) = -2 $x^{2}$ - x - 4 = -2 $x^{2}$ - x - 2 = 0 (x - 2)(x + 1) = 0 x = 2 and x = -1 We then use Equation 3: y = 2 + 4 = 6 y = -1 + 4 = 3 Therefore (2, 6) and (-1, 3) are solutions. Furthermore, the two graphs cross at (2, 6) and (-1, 3), so the answer is confirmed.