Chapter 9 - 9.1 - Linear and Nonlinear Systems of Equations - 9.1 Exercises - Page 635: 16

$(-5,2)$

Here, we have $x+4y=3$ This gives: $ x=3-4y$ Now, plug $x=3-4y$ into the second equation. $2(3-4y) -7y=-24$ $ 6-8y-7y=-24$ $-15y=-30\implies y=2$ Use the $y$ value and the equation above to solve for $x$: $ x=3-4(2)=-5$ Hence, $(x,y)=(-5,2)$