## Algebra and Trigonometry 10th Edition

$(\dfrac{4}{3},\dfrac{4}{3})$
Here, we have $6x-3y=4 \implies x=4-2y$ Now, plug $x=4-2y$ into the second equation. $6(4-2y)-3y=4$ $24-12y-3y=4$ $15y=20 \implies y=\dfrac{4}{3}$ Use the $y$ value and the equation above to solve for $x$: $x=4-2(\dfrac{4}{3})=\dfrac{4}{3}$ Hence, $(x,y)=(\dfrac{4}{3},\dfrac{4}{3})$