Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - 9.1 - Linear and Nonlinear Systems of Equations - 9.1 Exercises - Page 635: 8

Answer

(-3,2)

Work Step by Step

For this problem, Equation 1: x - 4y = -11 Equation 2: x + 3y = 3 For substitution we need to solve for a variable. In this problem, we will solve for x in Equation 2 to get Equation 3: x = 3 - 3y (Equation 3) We then substitute that into Equation 1 and solve for y: (3 - 3y) - 4y = -11 3 - 7y = -11 -7y = -14 y = 2 We then use Equation 3: x = 3 - 3(2) x = 3 - 6 x = -3 Therefore (-3,2) is a solution. Furthermore, the two graphs cross at (-3,2), so the answer is confirmed.
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