# Chapter 7 - 7.4 - Sum and Difference Equations - 7.4 Exercises - Page 539: 79b

$\dfrac{5}{12}$

#### Work Step by Step

From part (a), we have: $y=\sqrt {(1/3)^2+(1/4)^2} \sin 2t+\arctan \dfrac{1/4}{1/3}$ This implies that $y=\dfrac{5}{12}\sin 2t+0.6435$ The amplitude is the absolute value of the coefficient of a trigonometric function. Thus, we have: $Amplitude=|\dfrac{5}{12}|=\dfrac{5}{12}$

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