Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Equations - 7.4 Exercises - Page 539: 69


$\dfrac{\pi}{6}, \dfrac{5\pi}{6}$

Work Step by Step

We have $ \sin (x +\pi) -\sin x+1=1-2 \sin x=0$ After simplifying, we get $ \sin x \cos \pi +\cos x \sin \pi -\sin x+1=1-2 \sin x=0$ or, $\sin x-\sin x+1=1-2 \sin x=0$ or, $1= 2 \sin x$ or, $\sin x=\dfrac{1}{2}$ This yields: $ x=\dfrac{\pi}{6}, \dfrac{5\pi}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.