Algebra and Trigonometry 10th Edition

Published by Cengage Learning

Chapter 7 - 7.4 - Sum and Difference Equations - 7.4 Exercises - Page 539: 61

Answer

The identity is verified. $tan(θ+\pi)=tan~θ$

Work Step by Step

$tan(u+v)=\frac{tan~u+tan~v}{1-tan~u~tan~v}$ $tan~\pi=0$ $tan(θ+\pi)=\frac{tan~θ+tan~\pi}{1-tan~θ~tan~θ}=\frac{tan~θ+0}{1-tan~θ(0)}=tan~θ$

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