Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Equations - 7.4 Exercises - Page 539: 61


The identity is verified. $tan(θ+\pi)=tan~θ$

Work Step by Step

$tan(u+v)=\frac{tan~u+tan~v}{1-tan~u~tan~v}$ $tan~\pi=0$ $tan(θ+\pi)=\frac{tan~θ+tan~\pi}{1-tan~θ~tan~θ}=\frac{tan~θ+0}{1-tan~θ(0)}=tan~θ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.