Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Equations - 7.4 Exercises - Page 539: 59


The identity is verified. $sin(\frac{\pi}{6}+x)=\frac{1}{2}(cos~x+\sqrt 3~sin~x)$

Work Step by Step

$sin(u+v)=sin~u~cos~v+cos~u~sin~v$ $sin(\frac{\pi}{6}+x)=sin~\frac{\pi}{6}~cos~x+cos~\frac{\pi}{6}~sin~x=\frac{1}{2}~cos~x+\frac{\sqrt 3}{2}~sin~x=\frac{1}{2}(cos~x+\sqrt 3~sin~x)$
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