Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Exercises - Page 500: 8


(a) See the graph. (b) Quadrant I. (c) $\frac{20\pi}{9}$ and $-\frac{16\pi}{9}$

Work Step by Step

(b) $0\lt\frac{2\pi}{9}\lt\frac{\pi}{2}$, therefore, it lies in quadrant I. (c) $\frac{2\pi}{9}+2\pi=\frac{20\pi}{9}$ $\frac{2\pi}{9}-2\pi=-\frac{16\pi}{9}$
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