Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Exercises - Page 500: 31

Answer

$tan~\theta=-\frac{\sqrt {11}}{5}$ $cot~\theta=-\frac{5\sqrt {11}}{11}$ $csc~\theta=-\frac{6\sqrt {11}}{11}$ $cos~\theta=\frac{5}{6}$ $sin~\theta=-\frac{\sqrt {11}}{6}$

Work Step by Step

$sec^2\theta=1+tan^2\theta$ $tan^2\theta=(\frac{6}{5})^2-1=\frac{11}{25}$ $tan~\theta=-\frac{\sqrt {11}}{5}$ $cot~\theta=\frac{1}{tan~\theta}=-\frac{5}{\sqrt {11}}=-\frac{5\sqrt {11}}{11}$ $csc^2\theta=cot^2\theta+1=\frac{25}{11}+1=\frac{36}{11}$ $csc~\theta=-\frac{6}{\sqrt {11}}=-\frac{6\sqrt {11}}{11}$ $cos~\theta=\frac{1}{sec~\theta}=\frac{1}{\frac{6}{5}}=\frac{5}{6}$ $sin~\theta=\frac{1}{csc~\theta}=\frac{1}{-\frac{6}{\sqrt {11}}}=-\frac{\sqrt {11}}{6}$
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