Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Exercises - Page 500: 29

Answer

$A=523.6~in^2$

Work Step by Step

$150°=150°(\frac{\pi~rad}{180°})=\frac{5\pi}{6}~rad$ $A=\frac{1}{2}r^2θ$ $A=\frac{1}{2}·20^2·\frac{5\pi}{6}=\frac{500\pi}{3}=523.6~in^2$
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